2j^2-j-3=0

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Solution for 2j^2-j-3=0 equation:


Simplifying
2j2 + -1j + -3 = 0

Reorder the terms:
-3 + -1j + 2j2 = 0

Solving
-3 + -1j + 2j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-1 + -1j)(3 + -2j) = 0

Subproblem 1

Set the factor '(-1 + -1j)' equal to zero and attempt to solve: Simplifying -1 + -1j = 0 Solving -1 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1j = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1j = 0 + 1 -1j = 0 + 1 Combine like terms: 0 + 1 = 1 -1j = 1 Divide each side by '-1'. j = -1 Simplifying j = -1

Subproblem 2

Set the factor '(3 + -2j)' equal to zero and attempt to solve: Simplifying 3 + -2j = 0 Solving 3 + -2j = 0 Move all terms containing j to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2j = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2j = 0 + -3 -2j = 0 + -3 Combine like terms: 0 + -3 = -3 -2j = -3 Divide each side by '-2'. j = 1.5 Simplifying j = 1.5

Solution

j = {-1, 1.5}

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